High School Science Investigation and Experimentation Standards
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1st Content StandardMotion deals with the changes of an object’s position over time. Inherent in any useful study of motion is the concept of force, which represents the existence of physical interactions. Although Newton’s laws provide a good platform from which to analyze forces, those laws do not address the origin of forces. Fundamental forces in nature govern the physical behavior of the universe. One of these fundamental forces, gravity, influences objects with mass but acts at a distance, or without any direct contact between the objects. The electromagnetic force is also a fundamental force that operates across a distance. These standards on motion and forces provide the foundation for understanding some key similarities. And differences between these two forces. A working knowledge of basic algebra and geometry is an essential prerequisite for studying these concepts. Motion deals with the changes of an object’s position over time. Inherent in any useful study of motion is the concept of force, which represents the existence of physical interactions. Although Newton’s laws provide a good platform from which to analyze forces, those laws do not address the origin of forces. Fundamental forces in nature govern the physical behavior of the universe. One of these fundamental forces, gravity, influences objects with mass but acts at a distance, or without any direct contact between the objects. The electromagnetic force is also a fundamental force that operates across a distance. These standards on motion and forces provide the foundation for understanding some key similarities. And differences. Between these two forces. A working knowledge of basic algebra and geometry is an essential prerequisite for studying these concepts. |
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Physics Motion and Forces (20% of CST: 12 items) ~ Q 1 - 2 [12 items] 1. Newton’s laws predict the motion of most objects. As a basis for understanding this concept: |
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~ Q 1 |
a. Students know how to solve problems that involve constant speed and average speed. |
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The rate at which an object moves is called its speed. Speed is measured in distance per unit time (e.g., meters/second). Velocity v is a vector quantity and therefore has both a magnitude---the speed—and a direction. If an object travels at a constant speed, a simple linear relationship exists between the speed, or rate of motion r; distance traveled d; and time t, as shown in d = rt. (eq. 1) If speed does not remain constant but varies with time, average speed can be defined as the total distance traveled divided by the total time required for the trip. |
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~ Q 1 |
b. Students know that when forces are balanced, no acceleration occurs; thus an object continues to move at a constant speed or stays at rest (Newton’s first law). |
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If an object’s velocity v changes with time t, then the object is said to accelerate. For motion in one dimension, the definition of acceleration a is a = Dv/Dt , (eq. 2) where the Greek capital letter delta (D) stands for “a change of.” Acceleration is defined as change in velocity per unit time. (Another way to state this definition is that acceleration is a change in distance per unit time per unit time, producing acceleration units of, for example, m/s2 [meters per second squared or meters per second per second].) Acceleration is a vector quantity and therefore has both magnitude and direction. A push or a pull (force) needs to be applied to make an object accelerate. Force is another vector quantity. A vector quantity, such as force, can be resolved into its x, y, and z components, Fx , Fy , and Fz . More than one force can be applied to an object simultaneously. If the forces point in the same direction, their magnitudes add; if the forces point in opposite directions, their magnitudes subtract. The net (overall) force can be calculated by adding forces along a line algebraically and keeping track of the direction and signs. If an object is subject to only one force, or to multiple forces whose vector sum is not zero, there must be a net force on the object. How- ever, if there is no net force on an object already in motion, that object continues to move at a constant velocity. An object at rest remains at rest if no net force is applied to it. This principle is Newton’s first law of motion. |
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~ Q 1 |
c. Students know how to apply the law F =ma to solve one-dimensional motion problems that involve constant forces (Newton’s second law). |
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If a net force is applied to an object, the object will accelerate. The relationship between the net force F applied to an object, the object’s mass m, and the resulting acceleration a is given by Newton’s second law of motion F = ma . (eq. 3) If mass is in kilograms (kg) and acceleration is in meters per second squared (m/s2), then force is measured in Newtons, with 1 Newton = 1 kilogram-meter per second squared (1 kg-m/s2). If the net force on an object is constant, then the object will undergo constant acceleration. When studying constant force, students should be able to make use of the following equations to describe the motion of an object in one dimension at any elapsed time t by calculating its velocity v and distance from the origin d: v = v0 + at , (eq. 4) d =d0 + v0t + 12 at 2 . (eq. 5) In these equations m is the mass, v0 is the initial velocity, d0 is the initial position (distance from origin) of the object, and t is the time during which the force F is applied. |
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~ Q 1 |
d. Students know that when one object exerts a force on a second object, the second object always exerts a force of equal magnitude and in the opposite direction (Newton’s third law). |
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Newton’s third law of motion is more commonly stated as, “To every action there is always an equal and opposite reaction.” The mutual reactions of two bodies are always equal and point in opposite directions. Mathematically stated, if object 1 pushes on object 2 with a force F12 then object 2 pushes on object 1 with a force F21 such that F21 = - F12 . (eq. 6) This universal law applies, for example, to every object on the surface of Earth. Trees, rocks, buildings, and cars, even the atmosphere, are all subject to the downward force of gravity. In all cases Earth exerts an equal and opposite upward push on the objects. Stars exist because of the balance between the inward force of gravity and the outward pressure of their hot interior. |
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~ Q 1 |
e. Students know the relationship between the universal law of gravitation and the effect of gravity on an object at the surface of Earth. |
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Since the time of Galileo’s reputed experiment of dropping objects from the tower of Pisa, it has been understood that in the absence of air resistance, all objects near Earth’s surface, regardless of their mass or composition, accelerate downward toward Earth’s center at 9.8 m/s2. Through Newton’s second law, this principle can be expressed as F = w = mg (where g = 9.8m/s2 is the acceleration due to gravity). (eq. 7) The gravitational force pulling on an object is called the object’s weight w and is measured in Newtons. |
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~ Q 1 |
f. Students know applying a force to an object perpendicular to the direction of its motion causes the object to change direction but not speed (e.g., Earth’s gravitational force causes a satellite in a circular orbit to change direction but not speed). |
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A force that acts on an object may act in any direction. The component of the force parallel to the direction of motion changes the speed of the object, and the components perpendicular to the motion change the direction in which the object travels. |
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~ Q 1 |
g. Students know circular motion requires the application of a constant force directed toward the center of the circle. |
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An object moving with constant speed in a circle is in uniform circular motion. The direction of motion continuously changes because of a force that always points inward toward the center of the circle. Such a centrally directed force is called a centripetal force. If the mass of the object is m, its speed is v, and the radius of the circle in which the object travels is r, then the magnitude of the force causing the circular Fc = mv2/r . (eq. 8) Examples of centripetal forces are the tension in a string attached to a ball that is swung in a circle, the pull of gravity on a satellite in orbit around Earth, the electrical forces that deflect electrons in a television tube, and the magnetic forces that turn a charged particle. |
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NE~ Q 1 |
h.* Students know Newton’s laws are not exact but provide very good approximations unless an object is moving close to the speed of light or is small enough that quantum effects are important. |
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Newton’s laws are not exact but are excellent approximations valid in domains involving low speeds and macroscopic objects. However, when the speed of an object approaches the speed of light (3 x 108 m/s), Einstein’s theory of special relativity is required to describe the motion of the object accurately. Among the major differences between Einstein’s and Newton’s theories of mechanics are that (1) the maximum attainable speed of an object is the speed of light; (2) a moving clock runs more slowly than does a stationary one; (3) the length of an object depends on its velocity with respect to the observer; and (4) the apparent mass of an object increases as its speed increases. The other domain in which Newtonian mechanics breaks down is that of very small objects, such as atoms or atomic nuclei. Here the wavelike nature of matter becomes important, and quantum mechanics better describes the submicroscopic world. Newtonian mechanics assumes that if the motion of a particle is measured with great accuracy and all the masses and forces that are involved are also known, it is always possible to predict with equally great accuracy the future state of motion of the particle. Quantum mechanics shows that such certainty is not always possible. Sometimes only the probability of an outcome can be predicted. |
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NE~ Q 1 |
i.* Students know how to solve two-dimensional trajectory problems. |
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Students can consider the problem of a ball of mass m thrown upward into the air at some angle. The motion of the ball will have horizontal and vertical components that are independent of one another. If air resistance is ignored, there will be no horizontal force acting against the ball to slow it down. While the ball is in flight then, only a single vertical force, gravity, is acting on the ball (e.g., F = w =mg downward). If students know the angle and the height from which the ball is thrown and the ball’s initial velocity, they will be able to predict the path of the ball and to calculate how high the ball will go, how far it will travel before it strikes the ground, and how long it will be in the air. |
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NE~ Q 1 |
j.* Students know how to resolve two-dimensional vectors into their components and calculate the magnitude and direction of a vector from its components. |
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In a two-dimensional system, two quantities are needed to describe a vector. A vector r can be completely specified by a magnitude r and an angle f or by its x and y components (i.e., rx and ry ). Simple trigonometry can be applied to resolve a vector into its components (e.g., rx = r cos f and ry = r sin f) and to calculate the magnitude and direction of a vector from its components (r 2 = rx 2 + ry 2 and tan f = ry /rx ). |
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NE~ Q 2 |
k.* Students know how to solve two-dimensional problems involving balanced forces (statics). |
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A body at rest that is subject to no net force is in static equilibrium. Examples of static equilibrium are a book resting on the surface of a table and a ladder leaning at rest against a wall. Because the book and table remain at rest does not imply that no forces act on these objects but does imply that the vector sum of all these forces is zero. In particular, the components of the forces in any particular direction sum to zero. Thus for an object that remains at rest, S Fy = 0, (eq. 9) where the Greek capital letter sigma (S) means to “sum over or add” and Fy represents the components in any chosen direction y of the forces acting on the object. One sample problem appears in Figure 2, “Calculation of Force.” Students are given the weight of a hanging object, the lengths of the ropes holding it in place, and the distance between the anchors. The students are asked to calculate the forces, called tension, along ropes of equal length. Students find this problem difficult because the vector force diagram they should use to solve the problem is often confused with the physical lengths of the ropes.
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NE~ Q 2 |
l.* Students know how to solve problems in circular motion by using the formula for centripetal acceleration in the following form:a = v2 / r |
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The speed of an object undergoing uniform circular motion does not vary, but the object’s direction does and hence the object’s velocity. Thus the object is constantly accelerating. The magnitude of this centripetal acceleration is ac = Fc /m = v2/r , (eq. 10) and the direction of the centripetal acceleration vector rotates so that it always points inward toward the center of the circle. |
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NE~ Q 2 |
m.* Students know how to solve problems involving the forces between two electric charges at a distance (Coulomb’s law) or the forces between two masses at a distance (universal gravitation). |
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Standard Set 5 for physics, “Electric and Magnetic Phenomena,” which appears later in this section, shows that the origin of the force between two masses and between two electric charges is entirely different. However, the forces involved, the gravitational and the electromagnetic forces, are both inverse square relationships. Coulomb’s law (in a vacuum) is written Fq = kq1q2/r2 , (eq. 11) where k = 9x109 Nm2/coul2, q1 and q2 are charges (positive [+] or negative [-]), r is the distance separating the charges, and Fq is the force resulting from the two charges. The force is repulsive if the charges are the same sign and attractive if they are different. Newton’s law of universal gravitation states that if two objects have masses m1 and m2, with centers of mass separated from each other by a distance r, then each object exerts an attractive force on the other; the magnitude of this force is Fg = Gm1m2/r2 , (eq. 12) where G is the universal gravitational constant, equal to 6.67 x 10-11 newton-m2/kg2. For the case of a small object falling freely near the surface of Earth, students should understand that g = Gme /re 2 = 9.8 m/s2 , (eq. 13) where me and re are the mass and radius of Earth. Students might be interested to know that Henry Cavendish’s measurement of G, completed around the year 1800, was the last piece of information needed to calculate the mass of Earth. |
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2nd Content StandardThe concept of energy was introduced and discussed several times in the lower grades, from the physical sciences through the life sciences. In fact, every process involves some transfer of energy. In Standard Set 2 energy is classified as kinetic, meaning related to an object’s motion, or as potential, meaning related to an object’s stored energy. The energy of a closed system is conserved. Another useful conservation law, conservation of momentum, is introduced and is shown to be a direct consequence of Newton’s laws. The power and importance of these conservation laws are that they allow physicists to predict the motion of objects without having to know the details of the dynamics and interactions in a given system. Through the standard sets introduced in the lower grade levels, students should have learned about forces and motion and the idea of energy. They should have been taught the role of energy in living organisms and the effects of energy on Earth’s weather. The standards presented earlier also call for student exposure to energy conservation, a concept that is essential to the topics contained in the high school physics standard sets 3, 4, and 5 and in several standard sets in chemistry and earth sciences. |
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Conservation of Energy and Momentum (20% of CST: 12 items) ~ Q 1l - 2 [12 items] 2. The laws of conservation of energy and momentum provide a way to predict and describe the movement of objects. As a basis for understanding this concept: |
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~ Q 1- 2 |
a. Students know how to calculate kinetic energy by using the formula E = (1/2)mv 2 . |
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